Can You Determine Whether or Not an Organism Can Ferment a Sugar if It Does Not Grow in the Broth

Objective:

  • To notice the ability of microorganisms to ferment the given Sugar.
  • To decide the ability to degrade amino acids.
  • To determine the ability of microorganism to produce gaseous end products in fermentation.


Principle:


A metabolic procedure performed by nigh all types of bacteria is known as fermentation. This will result in the production of ATP, the ultimate energy source of the organism. This will happen either in the presence or absenteeism of atmospheric oxygen. Leaner utilize the nutrients in their environment to produce ATP for their biological processes such as growth and reproduction. The enzyme systems in bacteria allow them to oxidize environmental nutrient sources. Leaner will utilize different energy sources in the medium depends on the specific enzymes of each bacteria. Many bacteria possess the enzymes system required for the oxidation and utilization of the elementary sugar, glucose. Some leaner have the power to degrade complex carbohydrates like lactose, sucrose or fifty-fifty polysaccharides. Such bacterium should possess the enzymes that should cleave the glycosidic bonds betwixt the carbohydrate units and the resulting simple carbohydrate can be transported into the jail cell. Lactose is a disaccharide consisting of the glucose and galactose connected past glycosidic bail. The bacteria which produce the enzyme lactase will break this bond and thus release complimentary glucose that tin can be easily utilized by the organism. The characteristics characteristic of the enzyme production in the bacteria enables them to use various carbohydrates and this will aid in the identification of unknown bacteria. Fermentation is best described by the degradation of glucose past Embden- Meyerhof pathway or Glycolytic pathway (Figure ane).

   Effigy 1: Embden- Meyerhof Pathway

 The carbohydrate fermentation blueprint may exist unique to a particular species or strain (Figure 2).

                                                            Figure 2: Saccharide fermentation pattern of unlike leaner

Phenol Red Sugar Fermentation Broth:


Phenol ruby-red broth is a general purpose fermentation media comprising of trypticase, sodium chloride, phenol red and a carbohydrate. The trypticase provides amino acids, vitamins, minerals and other nitrogenous substances making it a nutritious medium for a variety of organisms.  Sodium chloride helps in maintaining the osmotic residual and provides the essential electrolytes for the transport into the cell while the sugar acts as the energy source. The phenol red is the pH indicator and is initially neutral (pH 7). Information technology supports the growth of nearly organisms whether they are able to ferment carbohydrate or not.  When the bacterium is inoculated into the tube, the bacterium which ferments the saccharide volition consequence in the product of acid that will change the colour of phenol reddish. Fermentation reactions often begin with glycolysis. Glucose acts as an electron donor in the fermentation reaction, pyruvate, and metabolic product of glucose act as an electron acceptor. The other disaccharides and polysaccharides are hydrolyzed into glucose or converted into glucose and then the fermentation reaction will occur. Finally the reaction will result in the end products such as acid, ethanol, Hydrogen and Carbon dioxide and other compounds. This depends on the species of bacteria. Phenol red broth is a examination is differential for gram negative leaner.
When the organism ferments carbohydrates, acidic organic by products (Lactic acid, formic acid or acerb acid) is accumulated which turns the medium into yellowish color with reduction in the pH (acidic). The inverted Durham tubes will detect the presence of gas. The degradation of peptones in the broth may result in the production of alkaline cease products, which volition change the broth color to pinkish often at the meridian of the tube.

Annotation:

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Source: https://vlab.amrita.edu/?sub=3&brch=73&sim=1139&cnt=1

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